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1 x 3 x 5 + 2 x 6 x 10 + 4 x 12 x 20
=15 + 120 + 960
= 135 + 960
=1095
1 x5 x 7 + 2 x 10 x 14 + 4 x 20 x 28
=35 + 280 + 2240
= 2555
k nha

a) 3+2*x=15
2x=15-3
2x=12
x=12:2
x=6
Vậy x=6
b) 24-x=19
x=24-19
x=5
Vậy x=5
c) 29x-13=45
29x=45+13
29x=58
x=58:29
x=2
Vậy x=2
d) 5x-17=38
5x=38+17
5x=55
x=55:5
x=11
Vậy x=11
e) 50-2(x+1)=20
2(x+1)=50-20
2(x+1)=30
x+1+30/2
x+1=15
x=15-1=14
Vậy x=14
f)
3/5 X + 2X + 40 = 53
13/5 X = 53 - 40
13/5 X = 13
X = 13 : 13/5
X = 5
a/ A = 12 + 22 + 32 +...+ 202
=> A = 1 + 2.( 1 + 1 ) + 3( 1 + 2 ) +...+ 20.( 1 + 19 )
=> A = 1 + 2 + 1.2 + 3 + 2.3 +...+ 20 + 19.20
=> A = ( 1 + 2 + 3 +...+ 20 ) + ( 1.2 + 2.3 +...+ 19.20 )
=> A = 210 + ( 1.2 + 2.3 +...+ 19.20)
GỌI ( 1.2 + 2.3 + ... + 19.20 ) là B. Ta có:
B = 1.2 + 2.3 +...+ 19.20
3B = 1.2.3 + 2.3.( 4 - 1 ) +...+ 19.20.( 21 - 18 )
3B = 1.2.3 + 2.3.4 - 1.2.3 + ...+ 19.20.21 - 18.19.20
3B = 19.20.21
B = 19.20.7
B = 2660
Thay B vào A ta có:
A= 210 + 2660
A = 2870
Vậy A = 2870
b/ B= 1.2.3 + 2.3.4 + 3.4.5 +...+ 18.19.20
4B = 1.2.3.4 + 2.3.4.( 5-1 ) + 3.4.5.( 6-2 ) +...+ 18.19.20.( 21-17 )
4B= 1.2.3.4 + 2.3.4.5 - 1.2.3.4 + 3.4.5.6 - 2.3.4.5 +...+ 18.19.20.21 - 17.18.19.20
4B = 18.19.20.21
B = \(\frac{18.19.20.21}{4}\)
B= 18.19.5.21
B = 34200
a)10+2(x+1)=20
2(x+1)=20-10
2(x+1)=10
(x+1)=10/2
x+1=5
x=5-1
x=4
Bài 1:
a; (\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\)) x \(\dfrac{3}{4}\) = \(\dfrac{1}{4}\)
\(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) : \(\dfrac{3}{4}\)
\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) x \(\dfrac{4}{3}\)
\(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{3}\)
\(\dfrac{1}{4}x\) = \(\dfrac{1}{3}\) + \(\dfrac{1}{8}\)
\(\dfrac{1}{4}\) \(x\)= \(\dfrac{8}{24}\) + \(\dfrac{11}{24}\)
\(\dfrac{1}{4}x=\dfrac{11}{24}\)
\(x=\dfrac{11}{24}:\dfrac{1}{4}\)
\(x=\dfrac{11}{24}\times4\)
\(x=\dfrac{11}{6}\)
b; \(\dfrac{12}{5}:x\) = \(\dfrac{14}{3}\) x \(\dfrac{4}{7}\)
\(\dfrac{12}{5}\) : \(x\) = \(\dfrac{8}{3}\)
\(x\) = \(\dfrac{12}{5}\) : \(\dfrac{8}{3}\)
\(x\) = \(\dfrac{12}{5}\) x \(\dfrac{3}{8}\)
\(x\) = \(\dfrac{9}{10}\)
x = 20/11
\(x+x\times2+x\times3+x\times5=20\\ x\times\left(2+3+5\right)+x=20\\x\times 10+x=20\\ x\times10=21\\ x=2,1\)
Uả x = 2,1 1 mà Bình
Sửa lại:
\(x+x\times2+x\times3+x\times5=20\\ x\left(1+2+3+5\right)=20\\ x\times11=20\\ x=\dfrac{20}{11}\)
Uả 20/11 sai hay sao mà 2 người
đâu có
x = 20/11 mà
ko tin tính thử đi
\(x+x\times2+x\times3+x\times5=20\)
\(xxxx=20\div\left(2+3+5\right)\)
\(xxxx=20\div10\)
\(xxxx=2\)
\(x=2:4\)
\(x=0,5\)
Cho mik sửa lại nha
\(x+x\times2+x\times3+x\times5=20\)
\(x\times1+x\times2+x\times3+x\times5=20\)
\(xxxx=20\div\left(1+2+3+5\right)\)
\(xxxx=20:11\)
\(xxxx=\dfrac{20}{11}\)
\(x=\dfrac{20}{11}\div4\)
\(x=5\)
Mình lại nhầm nữa cái cuối là \(x=\dfrac{5}{11}\)