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\(\frac{3^2.3^8}{27^3}=3x=>\frac{3^{10}}{\left(3^3\right)^3}=3x=>\frac{3^{10}}{3^9}=3x=>3^{10-9}=3x=>3x=3=>x=1\)
\(\left(\frac{2}{5}\right)^2+5\frac{1}{2}:\left(4,5-2\right)-0,2\)
\(=\frac{4}{25}+\frac{11}{2}:\frac{5}{2}-\frac{1}{5}\)
\(=\frac{4}{25}+\frac{11}{2}.\frac{2}{5}-\frac{1}{5}\)
\(=\frac{4}{25}+\frac{11}{5}-\frac{1}{5}\)
\(=\frac{4}{25}+\frac{55}{25}-\frac{5}{25}\)
\(=\frac{54}{25}\)
a) Đề sai
b) \(\left|x+\frac{4}{5}\right|=\frac{1}{7}\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{4}{5}=\frac{1}{7}\\x+\frac{4}{5}=\frac{-1}{7}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{7}-\frac{4}{5}\\x=\frac{-1}{7}-\frac{4}{5}\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{5}{35}-\frac{28}{35}\\x=\frac{-5}{35}-\frac{28}{35}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{-23}{35}\\x=\frac{-33}{35}\end{cases}}}\)
Vậy \(x=\frac{-23}{35}\)hoặc \(x=\frac{-33}{35}\)
b) 3x + x2 = 0
3x + x.x = 0
x.( 3+x) = 0
=> x = 0 hoac 3 + x = 0
thi x = -3
Vay x = 0 hoac x = -3
c) ( x -1 ) (x- 3 ) = 0
=> x - 1 = 0 hoac x - 3 = 0
x = 0 + 1 x = 0 + 3
x = 1 x = 3
Vay x =1 hoac x = 3
a, 1,5 +|2x - 2/3| = 3/2
|2x - 2/3| = 3/2 - 1,5
|2x - 2/3| = 0
<=> 2x - 2/3 = 0
<=> 2x = 0 + 2/3
<=> 2x = 2/3
<=> x = 2/3 : 2
<=> x = 1/3
Vậy x = 1/3
b, 3/4 - |1/4 - x| = 5/8
|1/4 - x| = 3/4 - 5/8
|1/4 - x| = 1/8
<=> 1/4 - x = 1/8
1/4 - x = /1/8
<=> x = 1/4 - 1/8
x = 1/4 - ( -1/8)
<=> x = 1/8
x = 3/8
Vậy x thuộc { 1/8 ; 3/8 }
a) 3/13 - 3/2 + 10/13
= (3/13 + 10/13) - 3/2
= 1 - 3/2
= -1/2
b) 4/7 - (-2/7) - 7/3
= 4/7 + 2/7 - 7/3
= 6/7 - 7/3
= -31/21
c) 2/3 - (-1/6) + 5/4
= 2/3 + 1/6 + 5/4
= 8/12 + 2/12 + 15/12
= 25/12
a, 3/13 - 3/2 + 10/13
= 3/13 + 10/13
= 1 - 3/2 = -1/2
b,4/7 - (-2/7) - 7/3
= 4/7 + 2/7 - 7/3
= 6/7 - 7/3
= 18/21 - 14/21
= 4/21
c, 2/3 - -1/6 +5/4
= 2/3 + 1/16 +5/4
= 128/192 + 12/192 + 240/192
= 380/192
= 95/4
không hiểu chỗ nào hỏi tui
\(\dfrac{5}{8}-\left[\dfrac{2}{3}-\left(\dfrac{5}{3}-\dfrac{1}{2}\right)\right]\)
\(=\dfrac{5}{8}-\left[\dfrac{2}{3}-\dfrac{5}{3}+\dfrac{1}{2}\right]\)
\(=\dfrac{5}{8}-\dfrac{2}{3}+\dfrac{5}{3}-\dfrac{1}{2}\)
\(=\left(\dfrac{5}{8}-\dfrac{1}{2}\right)+\left(\dfrac{2}{3}-\dfrac{5}{3}\right)\)
\(=\dfrac{1}{8}+-1\)
\(=\dfrac{1}{8}+-\dfrac{8}{8}\)
\(=-\dfrac{7}{8}\)