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( 2 x y + 2/15 ) x 3 = 4/5
( 2 x y + 2/15 ) = 4/5 : 3
( 2 x y + 2/15 ) = 4/15
2 x y = 4/15 - 2/15
2 x y = 2/15
y = 2/15 :2
y = 1/15
(2 x y + 2/15) x 3 = 4/5
2 x y + 2/15) = 4/5 : 3
2 x y + 2/15 = 4/15
2 x y = 4/15 - 2/15
2 x y = 2/15
y = 2/15 : 2
y = 1/15
7/9 x (2 - 1/3 x y) = 14/15
(2 - 1/3 x y) = 14/15 : 7/9
(2 - 1/3 x y) = 6/5
2 - y = 6/5 x 1/3
2 - y = 2/5
y = 2/5 + 2
y = 12/5
4/21 + 5 x y - 8/7 = 1/3
4/21 + 5 x y = 1/3 + 8/7
4/21 + 5 x y = 31/21
5 x y = 31/21 - 4/21
5 x y = 9/7
y = 9/7 : 5
y = 9/35
7/12 x y - 3/12 x y = 5
y x (7/12 - 3/12) = 5
y x 1/3 = 5
y = 5 : 1/3
y = 15
\(\frac{6}{7}.y+\frac{7}{18}+\frac{1}{7}.y=\frac{7}{18}\)
\(\frac{6}{7}.y+\frac{1}{7}.y+\frac{7}{18}=\frac{7}{18}\)
\(\frac{6}{7}.y+\frac{1}{7}.y=\frac{7}{18}-\frac{7}{18}\)
\(y.\left(\frac{6}{7}+\frac{1}{7}\right)=0\)
\(y.1=0\)
\(y=0:1\)
\(y=0\)
\(\left(x+7\right):3=14\)
\(\Leftrightarrow x+7=14.3\)
\(\Leftrightarrow x+7=42\)
\(\Rightarrow x=35\)
\(x-36:18=12\)
\(x-2=12\)
\(\Rightarrow x=14\)
\(2.\left(x+3\right)-1=15\)
\(2.\left(x+3\right)=16\)
\(x+3=16:2\)
\(x+3=8\)
\(\Rightarrow x=5\)
8 phút trước (18:30)
(X + 7) : 3 = 14
x + 7 = 14 x 3
x + 7 = 42
x = 42 -7
x = 35
X - 36 : 18 =12
x - 36 = 12x18
x - 36 = 216
x = 216 + 36
x = 252
2× ( x+ 3 ) -1 = 15
2 x ( x+3) = 15+1
2 x (x+3) = 16
x + 3 = 16 : 2
x + 3 = 8
x = 8+3
x = 11
( 2,4 x - 36) : \(1\dfrac{5}{7}\) = -14
( \(\dfrac{12}{5}\) x - 36) : \(\dfrac{12}{7}\) = -14
( \(\dfrac{12}{5}\) x -36 ) = -14 . \(\dfrac{12}{7}\)
\(\dfrac{12}{5}\) x -36 = -24
\(\dfrac{12}{5}\) x = -24 + 36
\(\dfrac{12}{5}\) x = 12
x = 12 : \(\dfrac{12}{5}\)
x = 5
(2,4*x-36):(1+5/7)=-14
(2,4*x-36): 12/7 =-14
2,4*x-36= -14*12/7
2,4*x-36= -4
2,4*x= -4+36
2,4*x= 32
x=32:2,4
x= 40/3 vậy x= 40/3
Tick nha
Câu 13 :
\(\left(-\frac{1}{4}+\frac{5}{8}\right)+-\frac{3}{5}\)
\(=\frac{3}{8}-\frac{-3}{5}\)
\(=\frac{39}{40}\)
Câu 14 :
\(M=\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)
\(=\frac{5}{9}.\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)\)
\(=\frac{5}{9}.1=\frac{5}{9}\)
Câu 15 :
\(E=\left(-\frac{3}{4}+\frac{2}{5}\right):\frac{3}{7}+\left(\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)
\(E=\left(-\frac{3}{4}+\frac{2}{5}+\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)
\(E=0\)
Câu 16 :
\(H=\frac{7}{8}:\left(\frac{2}{9}-\frac{1}{8}\right)+\frac{7}{8}:\left(\frac{1}{36}-\frac{5}{12}\right)\)
\(=\frac{7}{8}:\left(\frac{2}{9}-\frac{1}{8}+\frac{1}{36}-\frac{5}{12}\right)\)
\(=\frac{7}{8}:\frac{-7}{24}=-3\)
huhuhuhuhuhuhuhuhuhuhuhuhu giúp mk đi
Plssssssssssssssssssssssssssssssssssssssssssssss
\(a,36.19+36.81\)
\(=36.\left(19+81\right)\)
\(=36.100\)
\(=3600\)
\(b,8.12.125.5\)
\(=\left(125.8\right)\left(12.5\right)\)
\(=1000.60\)
\(=60000\)
\(c,\)chịu
c,7 x 9 + 14 x 27 + 21 x 36 / 21 x 27 + 42 x 81 + 63 x 108
7 x 9 + 14 x 27 + 21 x 36 / 7 x 3 x 9 x 3 + 14 x 3 x 27 x 3 + 21 x 3 x 36 x 3
1 / 3 x 3 + 3 x 3 + 3 x 3
1 / 9 + 9 + 9
1 / 27
1) \(\left|4-2x\right|.\dfrac{1}{3}=\dfrac{1}{3}\)
\(\left|4-2x\right|=\dfrac{1}{3}:\dfrac{1}{3}\)
\(\left|4-2x\right|=\dfrac{1}{3}.3\)
\(\left|4-2x\right|=1\)
=>\(4-2x=\pm1\)
+)\(TH1:4-2x=1\) +)\(TH2:4-2x=-1\)
\(2x=4-1\) \(2x=4-\left(-1\right)\)
\(2x=3\) \(2x=4+1\)
\(x=3:2\) \(2x=5\)
\(x=1,5\) \(x=5:2\)
Vậy x=1,5 \(x=2,5\)
Vậy x=2,5
2) \(\left(-3\right)^2:\left|x+\left(-1\right)\right|=-3\)
\(9:\left|x+\left(-1\right)\right|=-3\)
\(\left|x+\left(-1\right)\right|=9:\left(-3\right)\)
\(\left|x+\left(-1\right)\right|=-3\)
=> \(x+\left(-1\right)\) sẽ không có giá trị nào ( Vì giá trị tuyệt đối luôn luôn lớn hơn hoặc bằng 0 )
Vậy x = \(\varnothing\)
\(\left(\dfrac{3}{7}\right)^x.14^x=36\)
`=>` \(\left(\dfrac{3}{7}.14\right)^x=36\)
`=> 6^x = 6^2`
`=> x = 2`
Vậy `x = 2`
\(\left(\dfrac{3}{7}\right)^x\cdot14^x=36\\ =>\left(\dfrac{3}{7}\cdot14\right)^x=36\\ =>\left(3\cdot2\right)^x=36\\ =>6^x=36\\ =>6^x=6^2\\ =>x=2\)
Vậy: ...