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\(A=\frac{1}{1.6}+\frac{1}{6.11}+...+\frac{1}{n\left(n+5\right)}\)
\(A=\frac{1}{5}\left(\frac{5}{1.6}+\frac{5}{6.11}+...+\frac{5}{n\left(n+5\right)}\right)\)
\(A=\frac{1}{5}\left(\frac{6-1}{1.6}+\frac{11-6}{6.11}+...+\frac{n+5-n}{n\left(n+5\right)}\right)\)
\(A=\frac{1}{5}\left(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+...+\frac{1}{n}-\frac{1}{n+5}\right)\)
\(A=\frac{1}{5}\left(1-\frac{1}{n+5}\right)\)
\(A=\frac{n+4}{5n+25}\)
\(B=1.2+2.3+3.4+...+n\left(n+1\right)\)
\(3B=1.2.3+2.3.3+3.4.3+...+n\left(n+1\right).3\)
\(3B=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+n\left(n+1\right)\left[\left(n+2\right)-\left(n-1\right)\right]\)
\(3B=1.2.3-1.2.3+2.3.4-2.3.4+3.4.5-...-\left(n-1\right)n\left(n+1\right)+n\left(n+1\right)\left(n+2\right)\)
\(3B=n\left(n+1\right)\left(n+2\right)\)
\(B=\frac{n\left(n+1\right)\left(n+2\right)}{3}\)
mk làm đc,vs điều kiện bạn phải tick cho mk khi mk giải xog, ko đc tick cho ai
\(-\left(+51\right);-|-39|;-37;0;|-18|;-\left(-19\right);25\)
\(B=3^2+3^3+...+3^{99}\)
\(3B=3^3+3^4+...+3^{100}\)
\(3B-B=\left(3^3+3^4+...+3^{100}\right)-\left(3^2+3^3+...+3^{99}\right)\)
\(2B=3^{100}-3^2\)
\(B=\frac{3^{100}-9}{2}\)
\(2B+9=3^{2n+4}\)
\(\Leftrightarrow3^{2n+4}=3^{100}\)
\(\Leftrightarrow2n+4=100\)
\(\Leftrightarrow n=48\).
\(A=\frac{5.\left(2^2.3^2\right)^9.\left(2^2\right)^6-2.\left(2^2.3\right)^{14}.3^4}{5.2^{28}.3^{18}-7.2^{29}.3^{18}}\)
\(=\frac{5.2^{18}.3^{18}.2^{12}-2.2^{28}.3^{14}.3^4}{2^{28}.3^{18}.\left(5-7.2\right)}\)\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{18}}{2^{28}.3^{18}.\left(5-14\right)}\)
\(=\frac{2^{29}.3^{18}.\left(5.2-1\right)}{2^{28}.3^{18}.\left(-9\right)}=\frac{2.9}{-9}=-2\)
Vậy A=-2
\(8^5.7^5:56^4-4^2.3\\ =\left(8.7\right)^5:56^4-16.3\\ =56^5:56^4-48\\ =56-48\\ =8\)