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\(5.\left(x+35\right)=515\)
\(\Rightarrow x+35=515:5\)
\(\Rightarrow x+35=103\)
\(\Rightarrow x=103-35\)
\(\Rightarrow x=68\)
Mấy câu còn lại tương tự nhé !
\(5.\left(x+35\right)=515\)
\(x+35=515:5\)
\(x+35=103\)
\(x=103-35\)
\(\Rightarrow x=68\)
\(\left(x+40\right).15=75.12\)
\(\Rightarrow\left(x+40\right)=5.12\)[ rút gọn theo t/c đẳng thức ]
\(x+40=60\)
\(x=20\)
a.x-4300-(5250:1050.250)=4250
=>x-4300-1250=4250
=>x=4250+1250+4300
=>x=9800
b.x-6-(48-24.2:6-3)=100
=>x-6-(48-8-3)=100
=>x-6-37=100
=>x=100+37+6
=>x=143
c.20-[7.(x-3)+4]=2
=>7.(x-3)+4=20-2
=>7.(x-3)+4=18
=>7.(x-3)=18-4
=>7.(x-3)=14
=>x-3=14:7
=>x-3=2
=>x=2+3
=>x=5
d. [(6x-39):3].28=5628
=>(6x-39):3=5628:28
=>(6x-39):3=201
=>6x-39=201.3
=>6x-39=603
=>6x=603+39
=>6x=642
=>x=642:6
=>x=107
a: \(\Leftrightarrow5x-42=251\)
=>5x=293
hay x=293/5
b: \(\Leftrightarrow20-x=20\)
hay x=0
c: \(\Leftrightarrow x-4300-\dfrac{1}{50}=4250\)
\(\Leftrightarrow x=\dfrac{427501}{50}\)
d: =>(x+200):4=460-340=120
=>x+200=480
hay x=280
e: =>5+15(x+1)=500-480=20
=>15(x+1)=15
=>x+1=1
hay x=0
a. 5(x+35)=515
=> x+35=515:5
=> x+35=103
=> x = 103-35
=> x = 68
b. (x+40).15=75.12
=>(x+40).15=900
=>x+40=900:15
=>x+40=60
=>x=60-40
=>x=20
c.460+85.4=(x+200):4
=>460+340=(x+200):4
=>800=(x+200):4
=>800.4=x+200
=>3200=x+200
=>x=3200-200
=>x=3000
a) 310-(118-x)=217
118-x=310-217
118-x=93
x=118-93
x=25
b) 814-(x-305)=712
x-305=814-712
x-305=102
x =102+305
x = 407
c)5(x+35)=515
x+35 =515:5
x+35 =103
x =103-35
x =68
\(a,310-\left(118-x\right)=217\) \(c,5\left(x+35\right)=515\)
\(118-x=310-217\) \(x+35=515:5\)
\(118-x=93\) \(x+35=103\)
\(x=118-93\) \(x=103-35\)
\(x=25\) \(x=68\)
\(b,814-\left(x-305\right)=712\) \(\left[\left(6.x-39\right):3\right].28=5628\)
\(x-305=814-712\) \(\left(6.x-39\right):3=5628:28\)
\(x-305=102\) \(\left(6.x-39\right):3=201\)
\(x=102+305\) \(6.x-39=201x3\)
\(x=407\) \(6.x-39=603\)
\(6x=603+39\)
\(6x=642\)
\(x=107\)
\(e,2.x-138=2^3.2^2\)
\(2.x-138=32\)
\(2.x=32+138\)
\(2.x=170\)
\(x=170:2\)
\(x=85\)
a) 219-7x-7=100
212-7x=100
7x=112
x=16
các câu còn lại cứ thế mà làm
a: Đề thiếu vế phải rồi bạn
b: \(\left(x+40\right)\cdot15=75\cdot12\)
=>\(x+40=75\cdot\dfrac{12}{15}=5\cdot12=60\)
=>x=60-40=20
c: \(460+85\cdot4=\left(x+200\right):4\)
=>\(\left(x+200\right):4=460+340=800\)
=>x+200=3200
=>x=3200-200=3000
d: \(x-4300-\left(52520:1050\cdot250\right)=4250\)
=>\(x-4300-\left(5\cdot250\right)=4250\)
=>\(x-4300-1250=4250\)
=>x=4250+1250+4300=5500+4300=9800
e: \(x-6\left(48-24\cdot2:6-3\right)=100\)
=>\(x-6\left(48-48:6-3\right)=100\)
=>\(x-6\left(45-8\right)=100\)
=>\(x-6\cdot37=100\)
=>x=100+222=322
f: \(20-\left[7\left(x-3\right)+4\right]=2\)
=>\(7\left(x-3\right)+4=20-2=18\)
=>7(x-3)=14
=>x-3=2
=>x=3+2=5
Câu `a,` vế phải đâu.
\(b,\left(x+40\right).15=75.12\)
\(\left(x+40\right).15=900\)
\(x+40=900:15\)
`x + 40 = 60`
`x = 60 - 40`
`x = 20`
Vậy `x = 20`
`c, 460 + 85 . 4 = (x + 200) : 4`
` 460 + 340 = (x + 200) : 4`
` 800 = (x + 200) : 4`
`800 . 4 = x + 200`
` 3200 = x + 200`
` x = 3200 - 200`
` x = 3000`
Vậy `x = 3000`
`d, x - 4300 - (5250 : 1050 . 250) = 4250`
` x - 4300 - (5 . 250) = 4250`
` x - 4300 - 1250 = 4250`
` x - 4300 = 4250 + 1250`
` x - 4300 = 5500`
`x = 5500 + 4300`
`x = 9800`
Vậy `x = 9800`
`e, x - 6 .(48 - 24 . 2 : 6 - 3) = 100`
` x - 6 . (48 - 48 : 6 - 3) = 100`
` x - 6 . (48 - 8 - 3) = 100`
` x - 6 . (40 - 3) = 100`
` x - 6 . 37 = 100`
` x - 222 = 100`
` x = 100 + 222`
` x = 322`
Vậy `x = 322`
`f, 20 - [7 . (x - 3) + 4] = 2`
` 7 . (x - 3) + 4 = 20 - 2`
` 7 . (x - 3) + 4 = 18`
` 7 . (x - 3) = 18 - 4`
` 7 . (x - 3) = 14`
` x - 3 = 14 : 7`
` x - 3 = 2`
` x = 2 + 3`
` x = 5`
Vậy `x = 5`