Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
A = 1 + 1/110 + 1 + 1/90 + ... + 1 + 1 /2
A = 10 + 1/1.2+ 1 /2.3 + ... + 1/9.10 + 1/10.11
A = 10 + 1/1 - 1/2 + 1 /2 - 1/3 + ... + 1/9 - 1/10 + 1/10 - 1/11
A = 10 + 1/1 - 1/11
A = 10 + 10/11
A = 120/11
A = \(\frac{111}{110}+\frac{91}{90}+\frac{73}{72}+...+\frac{13}{12}+\frac{7}{6}+\frac{3}{2}\)
A = \(\left(\frac{1}{2}+1\right)+\left(\frac{1}{6}+1\right)+\left(\frac{1}{12}+1\right)+....+\left(\frac{1}{110}+1\right)\)
A = (1 + 1 + 1 +...+ 1) + \(\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{110}\right)\)
A = 10 + \(\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\right)\)
A = \(10+\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{10}-\frac{1}{11}\right)\)
A = \(10+\left(1-\frac{1}{11}\right)\)
A = \(10+\frac{10}{11}\)
A = \(\frac{120}{11}\)
6 2/7 + 7 3/5 + 8 6/9 + 9 1/4 + 2/5 + 5/7 + 1/3 x 3/4 + 1967
= 44/7 + 38/5 + 78/9 + 37/4 + 2/5 + 5/7 + 1/3 + 1967
= ( 44/7 + 5/7 ) + ( 38/5 + 2/5 ) + ( 26/3 + 1/3 ) + ( 37/4 + 3/4 ) +1967
= 7 + 8 + 9 + 10 + 1967
= 15 + 9 + 10 + 1967
= 24 + 10 + 1967
= 34 + 1967
= 2001
\(\frac{3}{12}+\frac{3}{20}+\frac{3}{30}+...+\frac{3}{110}\)
\(=3\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+...+\frac{1}{110}\right)\)
\(=3\left(\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+...+\frac{1}{10\cdot11}\right)\)
\(=3\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{10}-\frac{1}{11}\right)\)
\(=3\left(\frac{1}{3}-\frac{1}{11}\right)\)
\(=3\cdot\frac{8}{33}=\frac{8}{11}\)
https://olm.vn/hoi-dap/detail/63463423750.html
vào tham khảo đi mk nhác trình bày
3(1/2+1/6+1/12+.......+1/72+1/90) 3(1/1.2+1/2.3+1/3.4+......+1/8.9+1/9.10) 3(2-1/1.2+3-2/2.3+4-3/3.4+........+9-8/8.9+10-9/9.10) 3(1-1/2+1/2-1/3+1/3-1/4+........+1/8-1/9+1/9-1/10) 3(1-1/10) 3.9/10=27/10 K CHO MIK NHA
\(2\times169\times12-3\times68\times8-24\)
\(=24\times169-24\times68-24\)
\(=24\times\left(169-68-1\right)\)
\(=24\times100=2400\)
\(\frac{3}{12}+\frac{3}{20}+\frac{3}{30}+\frac{3}{42}+\frac{3}{56}+\frac{3}{72}+\frac{3}{90}+\frac{3}{110}\)
\(=\frac{3}{3\cdot4}+\frac{3}{4\cdot5}+\frac{3}{5\cdot6}+\frac{3}{6\cdot7}+\frac{3}{7\cdot8}+\frac{3}{8\cdot7}+\frac{3}{8\cdot9}+\frac{3}{9\cdot10}+\frac{3}{10\cdot11}\)
\(=3\cdot\left(\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}+\frac{1}{9\cdot10}+\frac{1}{10\cdot11}\right)\)
\(=3\cdot\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{10}-\frac{1}{11}\right)\)
\(=3\cdot\left(\frac{1}{3}-\frac{1}{11}\right)\)
\(=3\cdot\left(\frac{11}{33}-\frac{3}{33}\right)\)
\(=3\cdot\frac{8}{33}\)
\(=\frac{24}{33}\)
\(=\frac{8}{11}\)
Bài 3:
= 1- 1/2 + 1/2 -1/3 +...+ 1/98 -1/99
= 1- 1/99
= 98/99
Bài 4:
= 1/2*3 + 1/3*4 + 1/4*5 +...+ 1/10*11
= 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 +...+ 1/10 - 1/11
= 1/2 - 1/11= 9/22
\(2+\dfrac{3}{2}+\dfrac{3}{6}+\dfrac{3}{12}+...+\dfrac{3}{90}\)
\(=2+3\times\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{90}\right)\)
\(=2+3\times\left(\dfrac{1}{1\times2}+\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+...+\dfrac{1}{9\times10}\right)\)
\(=2+3\times\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{9}-\dfrac{1}{10}\right)\)
\(=2+3\times\left(1-\dfrac{1}{10}\right)\)
\(=2+3\times\dfrac{9}{10}\)
\(=2+\dfrac{27}{10}\)
\(=\dfrac{47}{10}\)
`2 + 3/2 + 3/6 + 3/12 + ... + 3/90`
`= 2 + 3 xx (1/2 + 1/6 + 1/12+ ... + 1/90)`
`= 2 + 3 xx (1/(1xx2) + 1/(2xx3) + 1/(3xx4) + ... + 1/(9xx10))`
`= 2 + 3 xx (1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/9 - 1/10)`
`= 2 + 3 xx (1 - 1/10) `
`= 2 + 3 xx 9/10`
`= 2 + 27/10`
`= 47/10`