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\(\dfrac{\text{45^{10^{ }}}.5^{10}}{75^{10}}=\dfrac{9^{10}.5^{10}.5^{10}}{5^{10}.5^{10}.3^{10}}=\dfrac{9^{10}}{3^{10}}=3^{10}\)
\(\dfrac{\left(0,8\right)^5}{\left(0,4\right)^6}=\dfrac{2^5.\left(0,4\right)^5}{\left(0,4\right)^6}=\dfrac{2^5}{0,4}=\dfrac{32}{0,4}=80\)
\(N=\dfrac{3^6\cdot2^6+3^6\cdot2^3+3^6}{-73}=\dfrac{3^6\left(2^6+2^3+1\right)}{-73}=-3^6\)
\(T=\dfrac{5^{20}\cdot3^{20}}{5^{30}\cdot3^{15}}=\dfrac{3^5}{5^{10}}\)
\(\dfrac{45^{10}.5^{20}}{75^{15}}=\dfrac{\left(5.3^2\right)^{10}.5^{20}}{\left(5^2.3\right)^{15}}=\dfrac{5^{21}.3^{20}}{5^{30}.3^{15}}=\dfrac{1.3^5}{5^9.1}=\dfrac{3^5}{5^9}\)
Mk làm hơi tắt còn kết quả mk vẫn để lũy thừa vì nếu => số
Chúc bn học tốt
\(\dfrac{45^{10}\cdot5^{20}}{75^{15}}\\ =\dfrac{\left(3^2\cdot5\right)^{10}\cdot5^{20}}{\left(5^2\cdot3\right)^{15}}\\ =\dfrac{\left(3^2\right)^{10}\cdot5^{10}\cdot5^{20}}{\left(5^2\right)^{15}\cdot3^{15}}\\ =\dfrac{3^{20}\cdot5^{30}}{5^{30}\cdot3^{15}}\\ =3^5\\ =243\)
Giải:
\(\dfrac{45^{10}.5^{20}}{75^{15}}\)
\(=\dfrac{\left(3.3.5\right)^{10}.5^{20}}{\left(3.5.5\right)^{15}}\)
\(=\dfrac{3^{10}.3^{10}.5^{10}.5^{20}}{3^{15}.5^{15}.5^{15}}\)
\(=\dfrac{3^{20}.5^{30}}{3^{15}.5^{30}}\)
\(=3^5=243\)
Vậy giá trị của biểu thức trên là 243.
Chúc bạn học tốt!!!
\(\dfrac{45^{10}.5^{20}}{75^{15}}=\dfrac{3^{20}.5^{30}}{3^{15}.5^{30}}=3^5=243\)
\(\dfrac{45^{10}.5^{20}}{75^{15}}=\dfrac{\left(3^2\right)^{10}.5^{10}.5^{20}}{\left(5^2\right)^{15}.3^{15}}\dfrac{3^{20}.5^{30}}{5^{30}.3^{15}}=3^5\)
\(\dfrac{2^{15}.9^4}{6^6.8^3}=\dfrac{2^{15}.\left(3^2\right)^4}{2^3.3^3.\left(2^3\right)^3}=\dfrac{2^{15}.3^8}{2^3.3^3.2^9}=\dfrac{2^{15}.3^8}{2^{12}.3^3}\) =\(2^3.8^5\)
a) \(\dfrac{2^{15}.9^4}{6^6.8^3}=\dfrac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^3}=\dfrac{2^{15}.3^8}{3^6.2^6.2^9}=\dfrac{2^{15}.3^8}{3^6.2^{15}}=3^2=9\)
b) \(\dfrac{45^{15}.5^{15}}{75^{15}}=\dfrac{\left(9.5\right)^{15}.5^{15}}{\left(3.25\right)^{15}}=\dfrac{9^{15}.5^{15}.5^{15}}{3^{15}.25^{15}}=\dfrac{\left(3^2\right)^{15}.5^{30}}{3^{15}.\left(5^2\right)^{15}}\)
\(\dfrac{3^{30}.5^{30}}{3^{15}.5^{30}}=3^{15}=14348907\)
c) \(\dfrac{8^{10}+4^{10}}{8^4+4^{11}}=\dfrac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\dfrac{2^{30}+2^{20}}{2^{12}+2^{22}}=\dfrac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}\)
\(=\dfrac{2^{20}}{2^{12}}=2^8=256\)
d) \(\dfrac{ \left(x^2\right)^5}{\left(x^5\right)^2}=\dfrac{x^{10}}{x^{10}}=1\)
a, \(4^3.5^3=\left(4.5\right)^3=20^3=8000\)
b, \(6^3.5^3=\left(6.5\right)^3=30^3=27000\)
c, \(8^2.5^2=\left(8.5\right)^2=40^2=1600\)
d, \(125^3.8^3=\left(125.8\right)^3=1000^3\)
e, \(5^2.6^2.3^2=\left(5.6.3\right)^2=90^2\)
M=\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{4^{20}\left(2^{20}+1\right)}{4^{25}+4^{15}}=\dfrac{4^{20}\left(2^{20}+1\right)}{4^{15}\left(4^{10}+1\right)}=\dfrac{2^{20}+1}{4^{10}+1}\)
T=\(\dfrac{45^{10}.5^{20}}{75^{15}}=\dfrac{9^{10}.5^{30}}{25^{15}.3^{15}}=\dfrac{3^{20}.5^{30}}{5^{30}.3^{15}}=3^5=243\)
từ đề bài ta có
\(\frac{45^5\cdot5^{10}}{75^5}=\frac{\left(15\cdot3\right)^5\cdot5^{10}}{\left(15\cdot5\right)^5}=\frac{15^5\cdot3^5\cdot5^{10}}{15^5\cdot5^5}=\frac{3^5\cdot5^5}{1}=15^5=759375\)

\(\dfrac{45^{10}.5^{10}}{75^{10}}\)
\(=45^{10}.5^{10}:75^{10}\)
\(=\left(45.5:75\right)^{10}\)
\(=3^{10}\)
\(\dfrac{45^{10}.5^{10}}{75^{10}}\) = \(\left(\dfrac{45.5}{75}\right)^{10}\) = \(\left(\dfrac{225}{75}\right)^{10}\) = 310