Phạm Trần Hoàng Anh
Giới thiệu về bản thân
`y . y^7 = y^1 . y^7 =` \(y^{1+7}\) `= y^8`
`y . y^7 = y^1 . y^7 = y1+7 = y^8`
2041 : 49 = 41 dư 32
\(\left\{{}\begin{matrix}-2x+3y=1\\\dfrac{1}{3}x-\dfrac{1}{2}y=-\dfrac{1}{6}\end{matrix}\right.=>\left\{{}\begin{matrix}-2x+3y=1\\2x-3y=-1\end{matrix}\right.=>\left\{{}\begin{matrix}0x=0\\-2x+3y=1\end{matrix}\right.\)
Vậy có vô số nghiệm
decorated
- Last month => thì quá khứ đơn
S + V(ed/C2) + O
`2.4.8.8.8.8`
`= 2. 2^2 . 2^3 . 2^3 . 2^3 . 2^3`
= \(2^{1+2+3+3+3+3}\)
= \(2^{15}\)
\(A=\dfrac{sin+cos}{sin-cos}\)
\(A=\dfrac{\dfrac{sin}{cos}+1}{\dfrac{sin}{cos}-1}\)
\(A=\dfrac{tan+1}{tan-1}\)
\(A=\dfrac{2+1}{2-1}\)
`A = 3`
`(5x - 1)^6 = 729`
`=> (5x - 1)^6 = 3^6`
`=> 5x - 1 = 3` hoặc `5x - 1 = -3`
`=> 5x = 4` hoặc `5x = -2`
`=> x = 4/5` hoặc `x = -2/5`
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`(2x + 1)^3 = -0,001`
`=> (2x + 1)^3 = (-0,1)^3`
`=> 2x + 1 = -0,1`
`=> 2x = -1001/1000`
`=> x = -1001/2000`
\(\left\{{}\begin{matrix}0,2x+0,5y=0,7\\4x+10y=9\end{matrix}\right.\)
<=> \(\left\{{}\begin{matrix}4x+10y=3,5\\4x+10y=9\end{matrix}\right.\)
<=> \(\left\{{}\begin{matrix}0x=5,5\left(ko\exists\right)\\4x+2y=3,5\end{matrix}\right.\)