Chiều cao hình bình hành là:

\(\dfrac{5}{6}:\dfrac{1}{4}=\dfrac{10}{3}\left(m\right)\)

Đáp số : \(\dfrac{10}{3}m\)

Công thức:

\(h=S:a\)

Vậy \(9030:42=215\)

\(5,1\times y-y:10=36,25\times4\)

\(5,1\times y-y\times0,1=145\)

\(\left(5,1-0,1\right)\times y=145\)

\(5\times y=145\)

\(y=145:5\)

\(y=29\)

\(\dfrac{2}{3}\times\dfrac{8}{17}+\dfrac{2}{3}\times\dfrac{5}{17}+\dfrac{2}{3}\times\dfrac{4}{17}\)

\(=\dfrac{2}{3}\times\left(\dfrac{8}{17}+\dfrac{5}{17}+\dfrac{4}{17}\right)\)

\(=\dfrac{2}{3}\times1\)

\(=\dfrac{2}{3}\)

\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times\left(1-\dfrac{1}{5}\right)\)

\(=\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times\dfrac{4}{5}\)

\(=\dfrac{1\times2\times3\times4}{2\times3\times4\times5}\)

\(=\dfrac{1}{5}\)

\(\left(1-\dfrac{3}{4}\right)\times\left(1-\dfrac{3}{7}\right)\times\left(1-\dfrac{3}{10}\right)\times\left(1-\dfrac{3}{13}\right)\times...\times\left(1-\dfrac{3}{97}\right)\times\left(1-\dfrac{3}{100}\right)\)

\(=\dfrac{1}{4}\times\dfrac{4}{7}\times\dfrac{7}{10}\times\dfrac{10}{13}\times...\times\dfrac{94}{97}\times\dfrac{97}{100}\)

\(=\dfrac{1\times4\times7\times10\times...\times94\times97}{4\times7\times10\times13\times...\times97\times100}\)

\(=\dfrac{1}{100}\)

\(2022^0+\left[100-\left(3^2+1\right)^2\right]\)

\(=2022^0+\left[100-\left(9+1\right)^2\right]\)

\(=2022^0+\left[100-10^2\right]\) (vì khi cộng như p/tính (9+1)^2 như trên thì ta tính trong ngoặc và giữ nguyên mũ )

\(=2022^0+\left[100-100\right]\)

\(=1+0\) (Đổi `2022^0` vì mọi số có mũ `0` thì biến đổi thành `1`)

\(=1\)

\(c,5.3^2+24:2^3\)

\(=5.9+24:8\)

\(=45+3\)

\(=48\)

1) have / her/ she/ What time / does/ science/.

=> What time does she have her sciene class.

2) Jane / Anna / are / now / What / doing / and/?

=> What are Jane and Anna doing now.

Mình sửa lại:

\(\dfrac{x+3}{15}=\dfrac{1}{3}\)

\(\Rightarrow\dfrac{x+3}{15}=\dfrac{5}{15}\)

\(\Rightarrow x+3=5\)

\(\Rightarrow x=5-3\)

\(\Rightarrow x=2\)

\(\dfrac{x+3}{15}=\dfrac{1}{3}\)

\(\Rightarrow x+3:15=\dfrac{1}{3}\)

\(\Rightarrow x+\dfrac{1}{5}=\dfrac{1}{3}\)

\(\Rightarrow x=\dfrac{1}{3}-\dfrac{1}{5}\)

\(\Rightarrow x=\dfrac{2}{15}\)