456
Giới thiệu về bản thân
\(\left(-18-12\right):5\)
\(=-\left(18+12\right):5\)
\(=-30:5\)
\(=-6\)
\(61,894+530,89\)
Vậy \(61,894+530,89=592,784\)
\(249,087-187,89\)
Vậy \(249-0,87-187,89=61,197\)
\(14,63\times34,7\)
Vậy \(14,63\times34,7=507,661\)
\(xx+x+5=125\)
\(xxx+5=125\)
\(3x+5=125\)
\(3x=125-5\)
\(3x=120\)
\(x=120:3\)
\(x=40\)
mình check lại nhé:
\(\left(\dfrac{3}{4}-\dfrac{1}{4}\times x\right)\times\dfrac{11}{33}=\dfrac{15}{8}\)
\(\left(\dfrac{3}{4}-\dfrac{1}{4}\times x\right)=\dfrac{15}{8}:\dfrac{11}{33}\)
\(\dfrac{3}{4}-\dfrac{1}{4}\times x=\dfrac{45}{8}\)
\(\dfrac{1}{4}\times x=\dfrac{3}{4}-\dfrac{45}{8}\)
\(\dfrac{1}{4}\times x=-\dfrac{39}{8}\)
\(x=-\dfrac{39}{8}:\dfrac{1}{4}\)
\(x=-\dfrac{39}{2}\)
`P/s `: @Ko Tên . Chj sửa rồi nhé!
\(\left(x-10\right).\left(25-x\right)=0\)
\(=>\left[{}\begin{matrix}x-10=0\\25-x=0\end{matrix}\right.=>\left[{}\begin{matrix}x=10\\x=25\end{matrix}\right.\)
Vậy \(x\in\left\{10;25\right\}\)
\(\left(\dfrac{3}{4}-\dfrac{1}{4}\times x\right)\times\dfrac{11}{33}=\dfrac{15}{8}\)
\(\left(\dfrac{3}{4}-\dfrac{1}{4}\times x\right)=\dfrac{15}{8}:\dfrac{11}{33}\)
\(\left(\dfrac{3}{4}-\dfrac{1}{4}\times x\right)=\dfrac{15}{8}\times3\)
\(\left(\dfrac{3}{4}-\dfrac{1}{4}\times x\right)=\dfrac{45}{8}\)
\(\dfrac{1}{2}\times x=\dfrac{45}{8}\)
\(x=\dfrac{45}{8}:\dfrac{1}{2}\)
\(x=\dfrac{45}{8}\times\dfrac{2}{1}\)
\(x=\dfrac{45}{4}\)
`3 × x + 4 × x = 140`
`(3 + 4) × x = 140`
`7 × x = 140`
` x = 140 ÷ 7`
` x = 20`
Vậy`x = 20`
Đề lỗi.Bạn xem lại đề!
s là phụ âm câm.